9500(x)=x^2-15x+50

Solution for 9500(x)=x^2-15x+50 equation:

9500(x)=x^2-15x+50

We move all terms to the left:

9500(x)-(x^2-15x+50)=0

We get rid of parentheses

-x^2+9500x+15x-50=0

We add all the numbers together, and all the variables

-1x^2+9515x-50=0

a = -1; b = 9515; c = -50;
Δ = b2-4ac
Δ = 95152-4·(-1)·(-50)
Δ = 90535025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{90535025}=\sqrt{25*3621401}=\sqrt{25}*\sqrt{3621401}=5\sqrt{3621401}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9515)-5\sqrt{3621401}}{2*-1}=\frac{-9515-5\sqrt{3621401}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9515)+5\sqrt{3621401}}{2*-1}=\frac{-9515+5\sqrt{3621401}}{-2}
$